- xRiotZxSSG
- Posts : 36

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Regist Date : 2010-06-19

## Simple Yet Devilish Math Problem

on Mon 18 Apr 2011, 21:00

I've been trying to decipher the answer to this math question for over a month. It's based on a question that arose from a spell I was trying to make via GUI.

Spell: Attack Dogs

Levels: 5

Dogs Spawn Per Lvl: 1 for lvls 1-2 2 for lvls 3-4 and 3 for lvl 5.

Were there 6 lvls, and of each 2, 2 dogs were spawned this would be simple.. But having an uneven factor makes it extremely complex. Anyone who may be better at math than me, come forward and answer this legendary inquire.

The final equation can be a decimal, but can not be a fraction of a number, or else it will register as 0. As far as I know if you have an integer and you use a real to set it the real being 0.60 for instance, it will register as 0, because integers only accept whole numbers..

Spell: Attack Dogs

Levels: 5

Dogs Spawn Per Lvl: 1 for lvls 1-2 2 for lvls 3-4 and 3 for lvl 5.

Were there 6 lvls, and of each 2, 2 dogs were spawned this would be simple.. But having an uneven factor makes it extremely complex. Anyone who may be better at math than me, come forward and answer this legendary inquire.

The final equation can be a decimal, but can not be a fraction of a number, or else it will register as 0. As far as I know if you have an integer and you use a real to set it the real being 0.60 for instance, it will register as 0, because integers only accept whole numbers..

- SickPVT
- Posts : 6

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Regist Date : 2011-03-27

## Re: Simple Yet Devilish Math Problem

on Tue 19 Apr 2011, 14:36

.. what exactly do you want to know?

- xRiotZxSSG
- Posts : 36

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Regist Date : 2010-06-19

## Re: Simple Yet Devilish Math Problem

on Tue 19 Apr 2011, 15:04

How to produce the number of dogs that the levels have been designated using math.

Usually you would just go, for each 5 levels, multiply once by the level of the ability. But that would create 5 dogs, I want three dogs using 5 levels, which I haven't figured out how to do mathematically.

There are easier ways to do it rather than an equation, but I want to know the answer to this divine question.

Usually you would just go, for each 5 levels, multiply once by the level of the ability. But that would create 5 dogs, I want three dogs using 5 levels, which I haven't figured out how to do mathematically.

There are easier ways to do it rather than an equation, but I want to know the answer to this divine question.

- TitanDeathSGFC
- Posts : 55

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Regist Date : 2010-10-09

## Re: Simple Yet Devilish Math Problem

on Tue 19 Apr 2011, 21:29

Maybe it could be something like this.

1x1=1

2x.5=1

3x.7=2.1

4x.5=2

5x.6=3

The devilish 3 doesn't want to be whole .

1x1=1

2x.5=1

3x.7=2.1

4x.5=2

5x.6=3

The devilish 3 doesn't want to be whole .

**s3rius**LTG- Posts : 1931

Réputation : 55

Regist Date : 2006-02-11

## Re: Simple Yet Devilish Math Problem

on Wed 20 Apr 2011, 01:04

When an integer is converted to a Real it is always rounded down.

So 0.6 becomes 0 and 1.6 becomes 1.

The formula:

( level / 2) + 0.5

Lvl 1: ( 1 / 2 ) + 0.5 = 0.5 + 0.5 = 1

Lvl 5: ( 5 / 2 ) + 0.5 = 2.5 + 0.5 = 3

So 0.6 becomes 0 and 1.6 becomes 1.

The formula:

( level / 2) + 0.5

Lvl 1: ( 1 / 2 ) + 0.5 = 0.5 + 0.5 = 1

Lvl 5: ( 5 / 2 ) + 0.5 = 2.5 + 0.5 = 3

....................

Anime is a prime example of why two nukes just weren't enough

Way to go, America!

- xRiotZxSSG
- Posts : 36

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Regist Date : 2010-06-19

## Re: Simple Yet Devilish Math Problem

on Thu 21 Apr 2011, 23:37

Excellent Math, mine for that matter sucks.

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